Given an array A of integers and integer K, return the maximum S such that there exists i < j with A[i] + A[j] = S and S < K. If no i, j exist satisfying this equation, return -1.
Example 1:
Input: A = [34,23,1,24,75,33,54,8], K = 60
Output: 58
Explanation:
We can use 34 and 24 to sum 58 which is less than 60.
Example 2:
Input: A = [10,20,30], K = 15
Output: -1
Explanation:
In this case it's not possible to get a pair sum less that 15.
Note:
1 <= A.length <= 100
1 <= A[i] <= 1000
1 <= K <= 2000
代码
Approach 1: Two Point
classSolution {publicinttwoSumLessThanK(int[] A,int K) {Arrays.sort(A);int i =0;int j =A.length-1;int ans =-1;while (i < j) {if (A[i] +A[j] >= K) { j--; } else { ans =Math.max(ans,A[i] +A[j]); i++; } }return ans; }}