# 81.Search-in-Rotated-Sorted-Array-II

## ้ข็ฎๅฐๅ

https://leetcode.com/problems/search-in-rotated-sorted-array-ii/

## ้ข็ฎๆ่ฟฐ

``````Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.

(i.e., [0,0,1,2,2,5,6] might become [2,5,6,0,0,1,2]).

You are given a target value to search. If found in the array return true, otherwise return false.

Example 1:

Input: nums = [2,5,6,0,0,1,2], target = 0
Output: true
Example 2:

Input: nums = [2,5,6,0,0,1,2], target = 3
Output: false

This is a follow up problem to Search in Rotated Sorted Array, where nums may contain duplicates.
Would this affect the run-time complexity? How and why?``````

## ไปฃ็ 

### Approach #1

https://segmentfault.com/a/1190000016825704

``````class Solution {
public boolean search(int[] nums, int target) {
if (nums == null || nums.length == 0) return false;

int start = 0, end = nums.length - 1;
while (start <= end) {
int mid = start + (end - start) / 2;
if (nums[mid] == target) return true;
if (nums[mid] > nums[start]) {
if (target < nums[mid] && target >= nums[start]) {
end = mid;
} else {
start = mid + 1;
}
} else if (nums[mid] < nums[start]) {
if (target > nums[mid] && target < nums[start]) {
start = mid + 1;
} else {
end = mid;
}
} else {
start++;
}
}
return false;
}
}``````

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