Given an array consists of non-negative integers, your task is to count the number of triplets chosen from the array that can make triangles if we take them as side lengths of a triangle.
Example 1:
Input: [2,2,3,4]
Output: 3
Explanation:
Valid combinations are:
2,3,4 (using the first 2)
2,3,4 (using the second 2)
2,2,3
Note:
The length of the given array won't exceed 1000.
The integers in the given array are in the range of [0, 1000].
代码
Approach #1
Time: O(n^2) && Space: O(1)
class Solution {
public int triangleNumber(int[] nums) {
Arrays.sort(nums);
int n = nums.length;
int cnt = 0;
for (int i = n - 1; i >= 2; i--) {
int l = 0;
int r = i -1;
while (l < r) {
if (nums[l] + nums[r] > nums[i]) {
cnt += r - l;
r--;
} else {
l++;
}
}
}
return cnt;
}
}