Given an array consists of non-negative integers, your task is to count the number of triplets chosen from the array that can make triangles if we take them as side lengths of a triangle.
Example 1:
Input: [2,2,3,4]
Output: 3
Explanation:
Valid combinations are:
2,3,4 (using the first 2)
2,3,4 (using the second 2)
2,2,3
Note:
The length of the given array won't exceed 1000.
The integers in the given array are in the range of [0, 1000].
代码
Approach #1
Time: O(n^2) && Space: O(1)
classSolution {publicinttriangleNumber(int[] nums) {Arrays.sort(nums);int n =nums.length;int cnt =0;for (int i = n -1; i >=2; i--) {int l =0;int r = i -1;while (l < r) {if (nums[l] + nums[r] > nums[i]) { cnt += r - l; r--; } else { l++; } } }return cnt; }}