# 237.Delete-Node-in-a-Linked-List

## 237. Delete Node in a Linked List

## 题目地址

<https://leetcode.com/problems/delete-node-in-a-linked-list/>

## 题目描述

```
Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Given linked list -- head = [4,5,1,9], which looks like following:

Example 1:
Input: head = [4,5,1,9], node = 5
Output: [4,1,9]
Explanation: You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function.

Example 2:
Input: head = [4,5,1,9], node = 1
Output: [4,5,9]
Explanation: You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function.

Note:
The linked list will have at least two elements.
All of the nodes' values will be unique.
The given node will not be the tail and it will always be a valid node of the linked list.
Do not return anything from your function.
```

## 代码

### Approach #1 Swap with Next Node

```java
/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
class Solution {
 //  Since we do not have access to the node before the one we want to delete
    public void deleteNode(ListNode node) {
      node.val = node.next.val;
      node.next = node.next.next;
    }
}
```


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