780.Reaching-Points

780. Reaching Points

题目地址

题目描述

A move consists of taking a point (x, y) and transforming it to either (x, x+y) or (x+y, y).
Given a starting point (sx, sy) and a target point (tx, ty), return True if and only if a sequence of moves exists to transform the point (sx, sy) to (tx, ty). Otherwise, return False.
Examples:
Input: sx = 1, sy = 1, tx = 3, ty = 5
Output: True
Explanation:
One series of moves that transforms the starting point to the target is:
(1, 1) -> (1, 2)
(1, 2) -> (3, 2)
(3, 2) -> (3, 5)
Input: sx = 1, sy = 1, tx = 2, ty = 2
Output: False
Input: sx = 1, sy = 1, tx = 1, ty = 1
Output: True
Note:
sx, sy, tx, ty will all be integers in the range [1, 10^9].

代码

Approach #1

Basic idea: If we start from sx,sy, it will be hard to find tx, ty. If we start from tx,ty, we can find only one path to go back to sx, sy. I cut down one by one at first and I got TLE. So I came up with remainder.
First line: if 2 target points are still bigger than 2 starting point, we reduce target points. Second line: check if we reduce target points to (x, y+kx) or (x+ky, y)
Time complexity I will say O(logN) where N = max(tx,ty).
class Solution {
while (sx < tx && sy < ty) {
if (tx < ty) {
ty %= tx;
} else {
tx %= ty;
}
}
return sx == tx && sy <= ty && (ty - sy) % sx == 0 ||
sy == ty && sx <= tx && (tx - sx) % sy == 0;
}