Given a 32-bit signed integer, reverse digits of an integer.
Example 1:
Input: 123
Output: 321
Example 2:
Input: -123
Output: -321
Example 3:
Input: 120
Output: 21
Note:
Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231, 231 − 1]. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.
代码
Approach #1 Pop and Push Digits & Check before Overflow
classSolution {publicintreverse(int x) {int rev =0;while (x !=0) {int pop = x %10; x /=10;if (rev >Integer.MAX_VALUE/10|| (rev ==Integer.MAX_VALUE/10&& pop >7)) return0;if (rev <Integer.MIN_VALUE/10|| (rev ==Integer.MIN_VALUE/10&& pop <-8)) return0; rev = rev *10+ pop; }return rev; }}