# 243.Shortest-Word-Distance

## 243. Shortest Word Distance

## 题目地址

<https://leetcode.com/problems/shortest-word-distance/>

## 题目描述

```
Given a list of words and two words word1 and word2, return the shortest distance between these two words in the list.

Example:
Assume that words = ["practice", "makes", "perfect", "coding", "makes"].
Input: word1 = “coding”, word2 = “practice”
Output: 3
Input: word1 = "makes", word2 = "coding"
Output: 1

Note:
You may assume that word1 does not equal to word2, and word1 and word2 are both in the list.
```

## 代码

### Approach #1 Brute Force

```java
class Solution {
  public int shortestistance(String[] words, String word1, String word2) {
    int minDistance = words.length;
    for (int i = 0; i < words.length; i++) {
      if (words[i].equals(word1)) {
        for (int j = 0; j < words.length; j++) {
          if (words[j].equals(word2)) {
            minDistance = Math.min(minDistance, Math.abs(i - j));
          }
        }
      }
    }

    return minDistance;
  }
}
```

### Approach #2 One Pass

```java
public int shortestDistance(String[] words, String word1, String word2) {
    int i1 = -1, i2 = -1;
    int minDistance = words.length;
    int currentDistance;
    for (int i = 0; i < words.length; i++) {
        if (words[i].equals(word1)) {
            i1 = i;
        } else if (words[i].equals(word2)) {
            i2 = i;
        }

        if (i1 != -1 && i2 != -1) {
            minDistance = Math.min(minDistance, Math.abs(i1 - i2));
        }
    }
    return minDistance;
}
```


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