Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If there isn't one, return 0 instead.
Note:
The sum of the entire nums array is guaranteed to fit within the 32-bit signed integer range.
Example 1:
Input: nums = [1, -1, 5, -2, 3], k = 3
Output: 4
Explanation: The subarray [1, -1, 5, -2] sums to 3 and is the longest.
Example 2:
Input: nums = [-2, -1, 2, 1], k = 1
Output: 2
Explanation: The subarray [-1, 2] sums to 1 and is the longest.
Follow Up:
Can you do it in O(n) time?
代码
Approach #1 HashMap
classSolution {publicintmaxSubArrayLen(int[] nums,int k) {int sum =0, max =0;HashMap<Integer,Integer> map =newHashMap();for (int i =0; i <nums.ength; i++) { sum = sum + nums[i];if (sum == k) { max = i +1; } elseif (map.containsKey(sum - k)){ max =Math.max(max, i -map.get(sum - k)); }if (!map.containsKey(sum)) {map.put(sum, i); } }return max; }}