1088.Confusing-Number-II

1088. Confusing Number II

题目地址

https://leetcode.com/problems/confusing-number-ii/

题目描述

We can rotate digits by 180 degrees to form new digits. When 0, 1, 6, 8, 9 are rotated 180 degrees, they become 0, 1, 9, 8, 6 respectively. When 2, 3, 4, 5 and 7 are rotated 180 degrees, they become invalid.

A confusing number is a number that when rotated 180 degrees becomes a different number with each digit valid.(Note that the rotated number can be greater than the original number.)

Given a positive integer N, return the number of confusing numbers between 1 and N inclusive.

Example 1:
Input: 20
Output: 6
Explanation: 
The confusing numbers are [6,9,10,16,18,19].
6 converts to 9.
9 converts to 6.
10 converts to 01 which is just 1.
16 converts to 91.
18 converts to 81.
19 converts to 61.

Example 2:
Input: 100
Output: 19
Explanation: 
The confusing numbers are [6,9,10,16,18,19,60,61,66,68,80,81,86,89,90,91,98,99,100].

Note:
1 <= N <= 10^9

代码

Approach #1 Backtracking

Time: O(1) && Space: O(1)

class Solution {
    Map<Integer, Integer> map = new HashMap<>();
    int res = 0;
    public int confusingNumberII(int N) {
        map.put(0, 0);
        map.put(1, 1);
        map.put(6, 9);
        map.put(8, 8);
        map.put(9, 6);
        helper(N, 0);
        return res;
    }
    private void helper(int N, long cur) {
        if (isConfusingNumber(cur)) {
            res++;
        }

        for (Integer i : map.keySet()) {
          long next = cur * 10 + i;
          if (next <= N && next != 0) {
              helper(N, next);
          }
        }
    }
    private boolean isConfusingNumber(long n) {
        long src = n;
        long res = 0;
        while (n > 0) {
            res = res * 10 + map.get((int) n % 10); 
            n /= 10;
        }
        return res != src;
    }
}

#2

class Solution {

    Map<Integer, Integer> map;
    int N;
    int res;
    public int confusingNumberII(int N) {

        map = new HashMap<>();
        map.put(0, 0);
        map.put(1, 1);
        map.put(6, 9);
        map.put(8, 8);
        map.put(9, 6);
        res = 0;
        if (N == 1000000000) {
            res++;
            N--;
        }

        this.N = N;
        search(0, 0);
        return res;
    }

    private void search(int p, int cur) {
        if (p > 9 || cur > N) {
            return;
        }
        if (isConfusing(cur)) {
            res++;
        }
        for (Integer d : map.keySet()) {
            if (p == 0 && d == 0) {
                continue;
            }
            search(p + 1, cur * 10 + d);
        }
    }

    private boolean isConfusing(int n) {
        long rot = 0;
        int tmp = n;
        while (n > 0) {
            rot = rot * 10 + map.get(n % 10);
            n /= 10;
        }
        return rot != tmp;
    }
}