A string S of lowercase English letters is given. We want to partition this string into as many parts as possible so that each letter appears in at most one part, and return a list of integers representing the size of these parts.
Example 1:
Input: S = "ababcbacadefegdehijhklij"
Output: [9,7,8]
Explanation:
The partition is "ababcbaca", "defegde", "hijhklij".
This is a partition so that each letter appears in at most one part.
A partition like "ababcbacadefegde", "hijhklij" is incorrect, because it splits S into less parts.
Note:
S will have length in range [1, 500].
S will consist of lowercase English letters ('a' to 'z') only.
代码
Approach #1 Greedy
Time: O(N) && Space: O(1)
classSolution {publicList<Integer> partitionLabels(String S) {int[] last =newint[26];for (int i =0; i <S.length(); i++) { last[S.charAt(i) -'a'] = i; }int j =0, anchor =0;List<Integer> ans =newArrayList();for (int i =0; i <S.length(); i++) { j =Math.max(j, last[S.charAt(i) -'a']);if (i == j) {ans.add(i - anchor +1); anchor = i +1; } }return ans; }}