1236.Web-Crawler
1236. Web Crawler
题目地址
https://leetcode.com/problems/web-crawler/
题目描述
Given a url startUrl and an interface HtmlParser, implement a web crawler to crawl all links that are under the same hostname as startUrl.
Return all urls obtained by your web crawler in any order.
Your crawler should:
Start from the page: startUrl
Call HtmlParser.getUrls(url) to get all urls from a webpage of given url.
Do not crawl the same link twice.
Explore only the links that are under the same hostname as startUrl.
代码
Approach 1: BFS
/**
* // This is the HtmlParser's API interface.
* // You should not implement it, or speculate about its implementation
* interface HtmlParser {
* public List<String> getUrls(String url) {}
* }
*/
class Solution {
public List<String> crawl(String startUrl, HtmlParser htmlParser) {
Set<String> set = new HashSet();
Queue<String> queue = new LinkedList();
String hostname = getHostname(startUrl);
queue.offer(startUrl);
set.add(startUrl);
while (!queue.isEmpty()) {
String currentUrl = queue.poll();
for (String url : htmlParser.getUrls(currentUrl)) {
if (url.contains(hostname) && !set.contains(url)) {
queue.offer(url);
set.add(url);
}
}
}
return new ArrayList<String>(set);
}
private String getHostname(String Url) {
String[] ss = Url.split("/");
return ss[2];
}
}
Last updated