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412.Fizz-Buzz
Write a program that outputs the string representation of numbers from 1 to n.
But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.
Example:
n = 15,
Return:
[
"1",
"2",
"Fizz",
"4",
"Buzz",
"Fizz",
"7",
"8",
"Fizz",
"Buzz",
"11",
"Fizz",
"13",
"14",
"FizzBuzz"
]
class Solution {
public List<String> fizzBuzz(int n) {
List<String> ans = new ArrayList<String>();
for (int num = 1; num <= n; num++) {
boolean divisibleBy3 = (num % 3 == 0);
boolean divisibleBy5 = (num % 5 == 0);
if (divisibleBy3 && divisibleBy5) {
ans.add("FizzBuzz");
} else if (divisibleBy3) {
ans.add("Fizz");
} else if (divisibleBy5) {
ans.add("Buzz");
} else {
ans.add(Integer.toString(num));
}
}
return ans;
}
}
class Solution {
public List<String> fizzBuzz(int n) {
// ans list
List<String> ans = new ArrayList<String>();
for (int num = 1; num <= n; num++) {
boolean divisibleBy3 = (num % 3 == 0);
boolean divisibleBy5 = (num % 5 == 0);
String numAnsStr = "";
if (divisibleBy3) {
// Divides by 3, add Fizz
numAnsStr += "Fizz";
}
if (divisibleBy5) {
// Divides by 5, add Buzz
numAnsStr += "Buzz";
}
if (numAnsStr.equals("")) {
// Not divisible by 3 or 5, add the number
numAnsStr += Integer.toString(num);
}
// Append the current answer str to the ans list
ans.add(numAnsStr);
}
return ans;
}
}
class Solution {
public List<String> fizzBuzz(int n) {
// ans list
List<String> ans = new ArrayList<String>();
// Hash map to store all fizzbuzz mappings.
HashMap<Integer, String> fizzBizzDict =
new HashMap<Integer, String>() {
{
put(3, "Fizz");
put(5, "Buzz");
}
};
for (int num = 1; num <= n; num++) {
String numAnsStr = "";
for (Integer key : fizzBizzDict.keySet()) {
// If the num is divisible by key,
// then add the corresponding string mapping to current numAnsStr
if (num % key == 0) {
numAnsStr += fizzBizzDict.get(key);
}
}
if (numAnsStr.equals("")) {
// Not divisible by 3 or 5, add the number
numAnsStr += Integer.toString(num);
}
// Append the current answer str to the ans list
ans.add(numAnsStr);
}
return ans;
}
}
Last modified 3yr ago