Given an array nums of n integers, are there elements a, b, c in nums such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note:
The solution set must not contain duplicate triplets.
Example:
Given array nums = [-1, 0, 1, 2, -1, -4],
A solution set is:
[
[-1, 0, 1],
[-1, -1, 2]
]
代码
Approach 1: 排序 + 2 Sum
一个For循环 + 双指针 (注意去重)
classSolution {publicList<List<Integer>> threeSum(int[] nums) {List<List<Integer>> result =newArrayList<List<Integer>>();Arrays.sort(nums);for (int i =0; i <nums.length-2; i++) {if (i >0&& nums[i] == nums[i -1]) {continue; }int left = i +1;int right =nums.length-1;while (left < right) {int tmp = nums[left] + nums[right]; // two sum if (tmp + nums[i] ==0) {result.add(Arrays.asList(nums[i], nums[left], nums[right])); left++;// 去重while (left < right && nums[left] == nums[left -1]) { left++; } } elseif (tmp + nums[i] <0) { left++; } else { right--; } } }return result; }}