Given a binary tree, you need to compute the length of the diameter of the tree. The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root.
Example:
Given a binary tree
1
/ \
2 3
/ \
4 5
Return 3, which is the length of the path [4,2,1,3] or [5,2,1,3].
Note: The length of path between two nodes is represented by the number of edges between them.
代码
Approach 1: DFS
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */classSolution {int ans =0;publicintdiameterOfBinaryTree(TreeNode root) {dfs(root)return ans; }publicintdfs(TreeNode node) {if (node ==null) return0;int L =dfs(node.left);int R =dfs(node.right); ans =Math.max(ans, L + R);returnMath.max(L, R) +1; }}